Full text: From Aristarchus to Diophantus (Volume 2)

I 
DETERMINATE EQUATIONS 485 
I. 9. a — x = m{b — x). 
I. 10. x + b = m(a—x). 
* 
I. 11. x+b = m(x — a). 
I. 39. (a + x)b + {b+x)a = 2 (a + b)x, \ 
or (a + b)x + (b + x)a = 2(a + x)b, V (a > b) 
or [a + b)x + [a + x)b = 2 (b + x)a. j 
Diophantus states this problem in this form, ‘ Given 
two numbers {a, b), to find a third number (x) such that 
the numbers 
(a + x)b, (b + x)a, (a + b)x 
are in arithmetical progression.’ 
The result is of course different according to the order 
of magnitude of the three expressions. If cob {5 and 3 
are the numbers in Diophantus), then (a + x)b < (b + x)a; 
there are consequently three alternatives, since {a + x)b 
must be either the least or the middle, and (b + x) a either 
the middle or the greatest of the three products. We may 
have 
(a + x)b < (a + b)x < {b + x) a, 
or (a + b)x < {a + x)b < (h + x)a, 
or {a + x)b < (b + x)a < {a + b)x, 
and the corresponding equations are as set out above. 
(ii) Determinate systems of equations of the first degree. 
I. 1. x + y = a, x — y = b. 
jl. 2. x + y = a, x = my, 
il. 4. x — y = a, x = my. 
I. 3. x + y = a, x = my + b. 
j I. 5. x + y = a, — x+-y = b, subject to necessary condition. 
m 
n 
I. 6. x + y = a, — x— -y=b. 
y ' m n J
	        
Waiting...

Note to user

Dear user,

In response to current developments in the web technology used by the Goobi viewer, the software no longer supports your browser.

Please use one of the following browsers to display this page correctly.

Thank you.