Full text: The collected mathematical papers of Arthur Cayley, Sc.D., F.R.S., sadlerian professor of pure mathematics in the University of Cambridge (Vol. 1)

270 ON CERTAIN FORMULAE FOR DIFFERENTIATION WITH APPLICATIONS [41 
which however is only a particular case of 
dx (1 — a?) 1 i (1 — 2 yx + y 2 )‘ 
d/3 
/3* (1 - 2@-x+- 2 
7 7 
= r 2 r 0 + I) Q _ ^x_2i 
I> + 1) p K P) 
.(10), 
/3 
which supposes 7 and - each less than unity. This formula was obtained in the case of 
(i + an integer, from a theorem, Leg. Gal. Int., tom. 11. p. 258, but there is no doubt 
that it is generally true. 
From (9), by writing x — cos 6, we have 
sin 2i 6dd rir(f+!) 
•(H). 
(1 — 27 cos 6 + y 2 ) 1 r (i + 1) 
which may also be demonstrated by the common equation in the theory of elliptic 
functions sin (c/> — 6) = 7 sin cf), as was pointed out to me by Mr [Sir W.] Thomson. It 
may be compared with the following formula of Jacobi’s, Grelle, tom. xv. [1836] p. 7, 
sin 21-1 6 d6 _ 1 f n cos (i — \)ddd ^ 
.(13), 
0 (1 — 27 cos 0 + y 2 ) 1 r (i + J 0 \/(l — 27 cos 6 + y 2 ) 
Consider the multiple integral 
w= i dxdy... 
J fix-a) 2 
{(iC — a) 2 + ... u 2 Y 
the number of variables being (2i +1) (not necessarily odd), and the equation of the 
limits being 
x 2 + y 2 . 
then, as will presently be shown, W may be expanded in the form 
(-)M* 
W = 7T i+ * & 
A 2- A r (A + 1) r (i + A + 
where A = a 2 + b 2 + and A extends from 0 to 00 . Suppose next 
dx d y ... 
£i-i(£ + w 2)-^£ (14), 
V 
.[ f 
J {(x-a) 2 ... 
u 2 Y {x 2 + ... v 2 ) u 
.(15): 
the number of variables as before, and the limits for each variable being — go , ao. We 
have immediately 
1 dW 
V 
-J 
J 0 
(£ + v 2 ) i+1 d% 
d£; 
W as before, i.e. 
V = 7T i+i S K 
(-)*M A 
d 
d£ 
2 2A r (A + 1) T (i + A + i) \duj J 0 (| + u 2 ) 1 (f + v 2 ) i+1 ’
	        
Waiting...

Note to user

Dear user,

In response to current developments in the web technology used by the Goobi viewer, the software no longer supports your browser.

Please use one of the following browsers to display this page correctly.

Thank you.