Full text: The collected mathematical papers of Arthur Cayley, Sc.D., F.R.S., late sadlerian professor of pure mathematics in the University of Cambridge (Vol. 10)

[656 
656] ON THE THEORY OF PARTIAL DIFFERENTIAL EQUATIONS. 135 
lUATIONS. 
«.] 
ction of certain 
articular case. 
3s is, in fact, a 
lies): and when 
the function in 
atial coefficients 
(as a letter not 
; it as a given 
instance, if H 
i, pqr — xyz = H 
Is upon that of 
we determine p, q, r as functions of x, y, z, the resulting value of pdx+qdy+rdz is 
an exact differential, and we have 
V = X + I (pdx + qdy + r dz), 
a solution containing three arbitrary constants, X, a, b, and therefore a complete solution 
of the proposed partial differential equation H = const. 
But (as is known) there is a different process of integration, for which the con 
jugate solutions are not required, and which has reference to a system of initial values 
x 0 , 2/ 0 , z 0 , p 0 , q 0 , r 0 : viz. if the independent solutions of (H, ©) = 0, are a, b, c, d, e, and 
if a 0 , b 0 , c 0 , d 0 , e 0 denote respectively the same functions of the initial variables that 
a, b, c, d, e are of x, y, z, p, q, r, then if from the equations 
a = a 0 , b = b 0 , c = c 0 , d = d Q , e = e 0 , H = const. 
we express p, q, r as functions of x, y, z and of x 0 , y 0 , z 0 , H, these last being regarded 
as constants, we have pdx + qdy+rdz an exact differential, and 
F = X + j (pdx + qdy +r dz), 
a solution containing the constants X, x 0 , y 0 , z 0 (that is, one supernumerary constant), and 
as such a complete solution. 
It is interesting to prove directly that pdx + qdy + rdz is an exact differential. 
I consider first the more simple case where the variables are p, q, x, y. Here p, q 
are to be found from the equations 
a = a 0 , b — b 0 , c = c 0 , H = const, 
and it is to be shown that pdx + qdy is an exact differential. 
Considering p, q, p 0 , q 0 as functions of the independent variables x, y, then dif 
ferentiating in regard to x, and eliminating we have 
da 
l 
da 
dq 
da 
da 0 
da 0 
dx 
T 
dq 
dx ’ 
dp ’ 
dp 0 ’ 
dq 0 
db 
+ 
db 
dq 
db 
dbo 
db 0 
dx 
dq 
dx’ 
dp ’ 
dpo ’ 
dq 0 
dc 
+ 
dc 
dq 
dc 
dco 
dc 0 
dx 
dq 
dx’ 
dp’ 
dp 0 ’ 
dq 0 
dE 
dx 
+ 
dE 
dq 
dq 
dx ’ 
dE 
dp ’ 
0 , 
0 
ion (H, ©) = 0, 
gate solutions)
	        
Waiting...

Note to user

Dear user,

In response to current developments in the web technology used by the Goobi viewer, the software no longer supports your browser.

Please use one of the following browsers to display this page correctly.

Thank you.