Full text: The collected mathematical papers of Arthur Cayley, Sc.D., F.R.S., late sadlerian professor of pure mathematics in the University of Cambridge (Vol. 13)

216 
ON waring’s formula. 
[925 
where 
fx = 
c d e 
&c. 
rp OP* OP'- 
lAj \AJ \X/ 
Hence, by Lagrange’s theorem, 
+ \mu m 1 
ode VI' 1 
.5 + «* 4 V + -J] H2 
)T 
" 1 
1.2.3 
4- &c., 
where the accents denote differentiations in regard to u. This is 
+ \m {(m — 3) c 2 u m ~ i + (m — 4) 2cdu m ~ 5 + (m — 5) (d 2 + 2ce) u m ~ 6 + .. .} 
— £ra {(m — 4) (m — 5) c 3 u m ~ 3 + ...} 
+ &c. 
+ u m ~ 2 . — me 
+ u m ~ 3 . — md 
+ . — me + \m. m — 3. c 2 
+ u m ~ 5 . — mf + \m. m — 4.2cd 
+ u m ~ 6 . — mg + \m. m — 5 . (d 2 + 2ce) — ^m. m — 4. m - 5 . c 3 
+ &c., 
which, putting therein u= — b and multiplying each side by (—) m , is the before- 
mentioned formula for (— ) w $a m : in that formula the series being continued only so 
far as the exponent of b is not negative. 
I notice also that we cannot easily, by means of the known formula 
Sa m /3P = Sa m . SaP - 8a m+ P, 
deduce an expression for Sa m 8 p ‘- in fact, forming the product of the series for Sa m , 
Sa p respectively, this product is identically equal to the series for Sa m+P , or we seem 
to obtain 0 = Sa. m S<x p — Sa m+P ] to obtain the correct formula, we have to take each 
of the three series only so far as the exponent of b therein respectively is not negative: 
and it is not easy to see how the resulting formula is to be expressed.
	        
Waiting...

Note to user

Dear user,

In response to current developments in the web technology used by the Goobi viewer, the software no longer supports your browser.

Please use one of the following browsers to display this page correctly.

Thank you.