Solution:
-l4-
1. According to the properties of the well known Bell curve, an
error of 0.02 in. in 90$ of the points correspond to a mean
square error of 0.02/1.64 = 0.0120 in. or, in other words:
jJL-J = 0.012 in.
Hr =
Mp* + m p 2+ H-Pgc
w
h
a
E
0.20 ZoZ
(5)
~ 1000 (^7000) 5.4
ITip = 0.0026 in. , measured on the publication
scale of the map (l: 25000).
Since the ground control is to be considered error-free
in this example, we have: ^
S c
Thus
, ¡JLp - 0.0117! in.
tn
In the case of a strip, 4p - M' »
thus, f~i - 0.01171 in.
3. mbd (feet) = 0-43B \ 44 >
\ f~-Lo z
here we have:
of 4^— (27000 ft.) = 117 82 ft.
o. ciò ih. J
= 0.01171 in.
M-o = - 0.01 mm. = ± 0.00039 in.
Z = H = 27000 ft.
f = 8.25 in.
S = 25000