Full text: Commissions III (Part 5)

-15- 
thus; 
4. 
mbd = 0.1(3(11782) u0.01171 (8.2g)(2gOOO) 
V 0.00039 (27000) 
76750 ft 
lli.f? miles 
^H = ^ M-otrp (U.35-1.25N+0.375N 2 -0.0625N 3 +0.015625N U )\ (2) 
h = - ytthI ” 6,3models - 
Thus, /i^ = 2 7.9 ft.. 
5- fV T = 
/C 2, £ 
+ m H + ^H, 
(10) 
m H = 0 25 •/.. Z = X5§§ (27000) = 6.75 ft} 
= M'H, 
0 
and in case of a strip, 
'U > 
ie, 
Thus, 
^H- 
= 27.9 ft. 
. ± 28.7 ft. 
^ H T satisfies the specifications. 
The values for mbd and derived from Figure 2 & 2-a agree with 
the above computed values. 
N.B. If the value obtained for /~l|_j is, for some reason, con 
sidered too high for the purpose of the map, then another value for 
mbd could be determined by proceeding backwards from a specified 
As an example, if in this case should not exceed 25 ft., chart 
2-a gives the mbd to be l4 miles.* Note that the fJ- H equation can 
* In such a case, proceed as follows: l) enterJLt|_j as ordinate in the 
lower part of the chart and proceed horizontally to the right to 
intersect the flight height. 2) go upward to intersect the focal 
length f. 3) read mbd on the ordinate. For smal 1 ranges ofU.u , 
Figs. 2-a and 3“ a are recommended.
	        
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