8 
2.3. The results. 
The normal equations were formed and solved according to the method of least 
squares. The corrections to the elements of the orientation are as follows: 
A7 Autograph. 
Interior orientation. 
19 
29 
39 
17E dx 
" -9E 
dx"- 
22E 
dXp 
11 
21 
31 
126 
19 
29 
39 
17E dy 
' -9E 
dy"- 
22E 
dy p 
11 
21 
31 
126 
dc 
“ *2f 271 + 336 N 2711 
- 0, 
dt 
= iK + 
dt 2 + 
-p 
dl 
= i (al i + 
dl-2 + 
a 3 ) 
273 3 
'274 3 
Exterior orientation. 
dx tT = 1^2701 
% = ~6^ 2702 
dz = if 2711 
1„ 0.2438 
** =-36?272 — dt 
d ? = + 
^ --iI^ N 274 -! M )+ a 
The following definitions are used: 
0.1043 
a 
0.1740 
dt 
dl 
( 5 ) 
( e) 
19 
29 
39 
19 
29 
39 
M 
= E dx" + E dx" + E 
dx" 
[vl = 
E dy' 
' + E dy‘ 
' + E 
dy" 
11 
21 
31 
11 
21 
31 
19 
29 
39 
19 
29 
39 
N 2701 
= 5 E 
11 
dx" - E 
21 
dx" - 4 
E dx" 
31 
H 2702 =3 5 ^ 
dy" - E 
21 
dy" - 
4 E dy" 
31 
N 271 
+ N 91 2 + 
^ 91 3 
IT = 
272 
= N 9 2l 
+ H 92 2 + 
N 9 2 3 
N 273 
= IT 
93 x 
+ *95 2 + 
^933 
H 274 = 
+ N 94 2 + 
( T ) 
at = ¿(«ax' + P ± ay ^ ) 
is=l 
ai = E (rX + s ± <Jy; ) 
i=l 11 1