rotation angle for the image-of 2.5 m pixel
resolution resampled from the 2.5 m pixel
resolution test image.
4-1 0 100m
EN ec
-2
= 3
NES
m 4
EM 5
EN 6c
EN 7
Test image of buildings of the
(2:1 rectangles).
10
Figure 8.
same shape
E
x
"S
N
A
(D)
c
©
(D)
u—
e
en
c
©
yy
Lj
0 i i + i + } +
0 10 20 30 40 50 60° 70 80 90
Rotation Angle (degree)
Figure 9. Flongatedness plotted against the
rotation angle for the image of 10 m pixel
resolution.
ps... 21 Rectangles: - :
p
2 Yep cages, y=
"S i =x. e, M
Ril NE ~~ Leser =
(D)
A
0d ree eeceo eene rmm mremnet riders :
RA
e
=
ESI ae Nee ied :
found
3,
0 UO À 7 —t(£] —ÓÀÀ MF ÀÀ-4 49
0 10 20 30 40 50 60 70 80:90
Rotation Angle (degree)
Figure 10. Elongatedness plotted against
the rotation angle for the image of 2.5 m
pixel resolution resampled from the 10 m
pixel resolution test image.
572
2:1 Rectangles
BE ipo mpm i oe Sa une nae" ens
um... "gb nn Ne =
% VR
[ACL SES SES ES Gn Gm mm 9m 4m €. 09 GG B G5 Um Ws CD "Gm | Gm mom Gm
oO
À
T
1
a
1
I
i
U
1
1
1
1
I
1
1
.
1
1
1
1
'
1
1
1
1
1
.
1
1
i
1
'
1
1
1
1
'
1
I
1
’
1
Elongatedness (x 4 x )
©
1 1 A
20 30°40 50 60 70
Rotation Angle (degree)
Figure 11. Elongatedness plotted against
the rotation angle for the image of 2.5 m
pixel resolution resampled from the 2.5 m
pixel resolution test image.
EN
=
=
m
=
=
vd
—
c
0 ^10 80
Figure 12. Test image of 10 m pixel
resolution displayed on a computer screen.
RULE 1
IF (area) IS (medium) AND
(elongatedness) IS (small) AND
(perimeter straightness) IS (medium)
(diagonal length of MBR) is (medium)
THEN
(object is a building)
AND
CE = 0,5
The role of the rules is to identify a
portion of the n-dimensional space spanned
by n descriptors as shown in Figure 13 for
a particular building candidate, to
calculate its probability as building,
to conclude whether or not it is a
building.
and