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The International Archives of the Photogrammetry, Remote Sensing and Spatial Information Sciences. Vol. XXXVII. Part B5. Beijing 2008
about 30 % increase of its determination.
Possibility of such an approach, gives a construction of this test.
It guarantees location of the test points in one vertical axis with
0.5 mm accuracy.
2. THEORY
Ta king into consideration arc G with class C created from
image points laying on the plumb line of the test, we can say
that: if tangent in a point M (ordinary point) in not parallel to
Oy axis, arc G in a neighborhood of the point M can be created
using equation (1), where function y(x) has a second continuous
derivative.
if curves has mathematical form: x=x(t), y=y(t), and taking into
account differential calculus and variations of variables, it is
clear that:
dy
V'(x) = f.
dt
>”(*)
dx d 2 y dy d 2 x
dt dr dr dr
i—Î
{ dt,
(6a)
using formulas above we obtain equations of center coordinates
(£, q) and radius of osculating circle R as parameterized
formulations (Gdowski, 1997).
v = v(x)
(i)
because equation of all circles series we can express by a
formula (2),
(x-*) 2 +(y-n) 2 -R-=0
(2)
(* ; +j V
*y-x'y
, (x ,2 +y'V
/7 = V + :
x’ v"-xy
where parameters are center coordinates (£, q) and radius R,
according to theory of osculating curves, we can claim, that we
obtain osculating circle to arc G in point M(xo.yo) by creating
function described below (3).
,2 \3 '2
R =
(x +y )
xy’-x”v1
(6b)
<K x) = <x-f) 2 +0*to-77) 2 -* 2
It fulfills conditions:
4>(x 0 ) = 0
<£•(*0) = °
3* ( x o) = 0
If we replace xowith x, the conditions (4) can be written as:
Because radius of curvature is equal to radius of osculating
circle we can say that center of circle is a center of curvature.
Set of curvature centers is an evolute, and its equation we can
express the same as it is in formula (6) (first and second
equation).
Geometric interpretation says that: curvature center is a normal
point to the curve in the point M, in which curve touches its
envelope, and the same it has limited position.
Intersection point of normal in point M with normal in
neighboring point Mi approach this position (Biemacki, 1954).
(x—£) 2 + (>' - tjŸ -R 2 =0
x - £ + v’O - rj) = 0
1+ v ,2 +.v ,, (v-/7) = 0
from third condition equation (5), calculating q, and from
second and first conditions ^and R, we obtain equations (6)
expressing center coordinates (£, q) and R - radius of osculating
circle (Biemacki, 1954).
Taking into consideration that plumb lines of test (in case of
fisheye lens) are conic sections (exactly fragments of ellipses)
we can describe them by equation (7) or as parametric formulas
(7a).
.v = a cos t
y = hsint
(7)
(1+v’ 2 ) 2 3
= M
0 < t < 2/r
(7a)
thus, as it was mentioned, that evolute is identical as envelope
of normal, we can derive it from equation of normal (8).
y(.v)[r->(x)] + .r-x = 0 (g)
Now, we insert parametric expression of ellipse (7a) into
(6) formulas (6b), we obtain: