]J. Die Sclilesisch-Posenscke Kette. 
509 
f 
S 2* 
Annahme: Schwarze Berg 0° 0' 0" 
Trebchen 
49 
38 
52 
+ 
A 
Kobelnik 
74 
17 
1 
+ 
B 
Guzdzin 
106 
45 
5 
+ 
C 
Chmilinko 
145 
10 
44 
+ 
D 
Tarnowo 
181 
51 
33 
+ 
E 
Kicin 
237 
0 
39 
+ 
F 
Schroda 
307 
6 
18 
+ 
G 
End gleich ungen: 
+ 5,602 = + 19,398 A — 1,650 B 
4- 11,590 = + 17,683 B 
-f 14,570 = 
— 13,421 = 
— 5,490 = 
— 11,131 = 
+ 11,044 = 
(a) 
— 2,202 0 — 1,869 D — 3,269 E — 2,769 F — 3,436 Q 
— 1,917 C — 1,917 D - 6,317 E — 2,983 F — 1,650 0 
+ 18,298 0 — 2,869 D — 3,702 E — 1,536 F — 2,036 G 
+ 18,464 D — 3,202 E — 1,869 F - 1,869 G 
+ 29,898 E — 4,102 F — 4,269 G 
+ 17,898 F — 2,269 G 
+ 19,064 G 
(6) 
+ 5,602 = + 19,398 A — 1,650 B 
+ 12,066 = + 17,543 B 
+ 16,653 = 
— 8,337 = 
+ 2,049 = 
— 6,809 = 
+ 12,082 = 
— 2,202 C — 1,869 D — 3,269 E — 2,769 F — 3,436 G 
— 2,104 C — 2,076 D — 6,595 E — 3,219 .F - 1,942 G 
+ 17,796 C — 3,330 D — 4,864 E — 2,236 F — 2,659 G 
+ 17,415 D — 5,207 E — 2,935 F — 2,927 G 
+ 23,982 E — 7,268 F — 7,180 G 
+ 13,933 F — 6,118 G 
+ 12,515 G 
A = + 6^704 
B = -f 1,025 
C = + 1,128 
D = — 0,221 
E = 4- 0,355 
F = — 0,065 
G = + 0,965