Full text: Die Märkisch-Schlesische und die Schlesisch-Posensche Kette und deren Ergänzungen (2. Theil, 2. Abtheilung)

f iS 
JE. Berechnung der geographischen Breite, Länge und der Azimuthe. ßQ3 
Verbesserungen der Polygonwinkel und der Azimuthe der Polygonseiten: 
= + (69) 
M>i = - (66) + (67) 
W 2 = - (48) + (49) 
»08 = - (33) 
*04 = - (20) + (21) 
Z05 = - (8) + (9) 
*0</= + (2) 
w n 
(V'i) 
(SPa) = w o + w i 
($P 3 ) = + *0! + W 2 
(^4) = + *0 X + W 2 + W 3 
{$5) = ™ 0 + W 1 + W 2 + *0 3 + W 4 
fa«) = + *01 4~ *02 4" *03 4* *04 4“ *00 
($PiO= V 
Verbesserungen der Logarithmen der Polygonseiten: 
(Ol) = 4- 17,28 (65) — 17,28 (66) — 5,55 (71). 
(°a) = 4- 4,04 (47) — 4,04 (48) - 24,18 (50) -f 20,24 (51) 4- 18,80 (56) - 33,35 (57) 4- 14,55 (58) 4- 17,28 (65) 
— 17,28 (66) — 15,22 (69) + 30,70 (70). 
(0*3) = 4- 13,62 (32) — 13,62 (33) + 33,09 (39) — 59,63 (40) + 26,54 (41) + 4,04 (47) — 4,04 (48) — 3,94 (50) 
4- 6,72 (61) — 6,72 (52) 4- 18,80 (56) — 33,35 (57) + 14,55 (58) + 17,28 (65) — 17,28 (66) — 14,90 (67) 
4- 14,90 (68) — 15,22 (69) + 30,70 (70). 
(rf 4 ) = __ 22,64 (1) + 22,64 (2) — 23,80 (4) — 12,59 (7) 4- 12,59 (8) 4- 16,71 (9) 4- 0,37 (10) — 15,01 (13) 
+ 15,01 (14) + 11,97 (21) — 19,83 (22) - 13,86 (25) + 13,86 (26) — 16,88 (31) — 11,53 (34) — 13,85 (37). 
«> = — 22,64 (1) 4- 22,64 (2) - 23,80 (4) 4- 16,71 (9) + 0,37 (10) - 15,01 (13) + 15,01 (14) 4* 11,97 (21) 
— 19,83 (22) — 11,92 (26). 
(°i0 = — 23,80 (4) + 16,71 (9) 4- 0,37 (10) - 1,65 (14). 
Verbesserungen der Grössen £ und tj: 
(SO = 
= 4* 
[(«.) + 
0,93 
(spOI 
85 
M = 
- ÌW - 
478,78 
1922 
(!>) = 
= 4- 
[ w + 
59,26 
faO] 
646 
M = 
- ÌK) - 
7,48 
M J : 
230 
(S») = 
= - 
[( ff s) - 
310,29 
W] 
2149 
M = 
- [W + 
1,43 
(?>■<)] : 
146 
(SO = 
= 4- 
\iOli + 
26,58 
(Vi)\ 
255 
M = 
- K°i) - 
16,68 
iv>)\ ■ 
202 
(£5) = 
= + 
ih») + 
47,55 
W] 
393 
(Vb) = 
- EM - 
9,32 
I9J)} ■ 
174 
(!.')= 
= - 
[(*.*)+ 
81,86 
W] 
489 
M= 
+ 1(0- 
5,42 
Mi 
126 
Verbesserungen der Coordinaten der Polygon-Winkelpunkte: 
M = 
(SO 
W = 
M 
w - 
(ßi) + 
(£2) 
w = 
M 4- 
(«3) = 
(S0 + 
(£2) 
+ (Is) 
w = 
M + 
W + fe) 
(<) = 
(1.) + 
(« 
4- (£3) 4- (I4) 
\yJ) = 
M + 
te) + M 
+'M 
( X b) = 
(S0 + 
(£2) 
4- (£3) 4- (£4) 4- (£5) 
<y0 = 
M + 
M 4- M 
4- M 4- 
M = di') 
Hanpt-Dreiecke 
II. 
(y*')= 
M 
G 3
	        
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