A. Die Hannoversche Dreieckskette. 
07 
Berechnung der Koordinatenunterschiede. 
1. Ahlsburg — Moosberg. 
sin = 
sin AMe • 
sin AMeMo 
sin AMoMe 
O / Il O 1 II 
AMeMo = 17 20 33,i°3—(6) + (7) AMoMe — 66 52 16,912—(8) + (9) 
9/474 3379-°! — 6 7,4* (6) + 67,42 (7) 9,963 6109.1 — 8 /99 ( 8 ) + 8 /99 (9) 
9,963 6109.1 
9,510 7269.9 
4,759 8120.7 = log AMe 
— 52.6 - Aj — Ai 
3374-5 = lo g J i — ] °S A 
4,270 8712.5 = log ¿1 
9/997 8 333- 1 + 4,xi (1) — 2,11 (3) — log sin t x 
8,998 4391.4 — 210,28 (1) + 210,28 (3) = log cos /1 
4.268 7045.6« 
3.269 3103.9 
log(ji —j,) = 4,2.68 7045.6« + 2,11 (1) — 2,11 (3) — 67,42 (6) 4- 67,42 (7) +8,99 (8) 
— 8 /99 (9) 
log (#2 — = 3,269 3103.9 — 210,28(1)4-210,28(3)—67,42(6)4-67,42(7)4-8,99(8) 
— 8 ,99 (9) 
2. Moosberg — Winnefeld. 
. sin MeAMo . sin MoMeB . sin MoBW 
sin A 2 — sin AMe • ————— ——-— ; ————— : 
sin MeMoA . sin MoBMe . sin MoWB 
MeAMo = 95 47 14,175— (2)4- (3) 
MoMeB = 58 6 12,357— (5)+ (6) 
MoBW =41 19 39,870 — (12)+ (13) 
9/997 7808.0 + 2,13 (2)— 2,13 (3) 
9/928 9094.0 — 13,10 (5)4-13,10 (6) 
9,819 7842.7 — 23,94 (12) 4- 23,94 (13) 
9,746 4744.7 
9,804 2007.3 
9,942 2737.4 
4,759 8120.7 = log AMe 
— 13.7 = Ai — Al 
4325.2 = log — log 
4,702 5169.6 = log i 2 
9,973 4534-4 + 7,59 00“ 7,59 (3)+ 7,59 ( 8 ) — 7,59 (11) = log sin ^ 
9,530 4889.0 — 58,39 (1) 4- 58,39 (3) — 58,39 (8) + 58,39 (11) = log cos 4 
4,675 9704.0« 
4,233 0058.6 
log(44— Ai) = 4,675 9704.0« + 7,59 (i) + 2,I3 (2) —9,72 (3) —13,10 (5)+ 13,10 (6) 
+ 16,58 (8) —8,99 (9) — 7,59(n) — 23,94(i2) + 45,86(13) 
— 21,92(14)+ 0,19 (16) —0,19(17) 
log(Jf a —x I ) = 4 ,233 0058.6 — 58,39 (1) + 2,13 (2) + 56,26 (3)—13,10 (5) +13,10 (6) 
— 49,40 (8) —8,99 (9)+ 58,39(11) — 23,94(i2) + 45,86(13) 
— 21,92(141 + 0,19(16)— 0,19(17) 
O / II 
MeMoA = 66 52 16,912— (8) + (9) 
MoBMe = 43 51 7,529 — (13) + (14) 
MoWB =89 29 8,808 — (16)+ (17) 
9,963 6109.1— 8,99 (8) + 8,99 (9) 
9,840 6073.1 — 21,92 (13) + 21,92 (14) 
9,999 9825.1 — 0,19(16)+ 0,19(17) 
9,804 2007.3