176
Netzausgleichung.
9,982 5528.9 — 6,09 (1) + 6,09 (3)
9,874 8302.4—18,59 (21) + 18,59 (22)
9,97^ 7876;2 — r 4,39 ( 6 ) + *4,39 ( 8 )
9,774 1707.5
9,774 1708 1
— 0.6
0 = — 0,030 — 0,3045
- °, I 995
9,8770364.5 — 18,38 (7)+ 18,38 (8)
9,998 0095.8 — 2,02 (2) + 2,02 (3)
9,899 1247.8 + 16,19 ( l8 ) — 9 ( 2I )
9,774 1708.1
(0 -h 0,1010 (2)+ 0,2035 (3) —0,7195 (6)+ 0,9190 ( 7 )
(8) — 0,8095 (18) — 0,1200 (21) + 0,9295 (22)
VIII. Belchen — Sausheim — Basis nördlich.
O / 11
Belchen = 31 38 44,836 — (24) + (26)
Sausheim = 80 46 8,782 — (18) + (19)
Basis nördlich — 67 35 7,431 — (5) + (6)
Summe = i8q o 1,049
i8o°+£ = i8o o 1,598
o = — 0,549 — (5) + (6) — (18) + (19) — (24) + +6)
IX. Ballon — Sausheim — Basis nördlich.
O / 11
Ballon = 46 11 12,763 — (32) + (34)
Sausheim — 63 23 24,716 + (18) — (20)
Basis nördlich = 70 25 23,291 — (6) + (9)
Summe =180 o 0,770
i8o°+t=i8o o 1,073
o = — 0*303 — (6) + (9) + (18) — (20) _ (32) + (34)
X. Ballon — Belchen — Basis nördlich.
Ballon = 25 30 45,837 - (32)+ (33)
Belchen = 16 28 45,212 — (25) + (2b)
Basis nördlich = 138 o 30,722— (5)+ (9)
Summe =180 o 1,771
i8o° + f=i8o o 1,433
0 = + °,33 8 — (5) + (9) — ( 2 5) + (* 6 ) — (l 2 ) + (> 3)
XI. Basis nördlich — Belchen — Sausheim — Ballon.
sin BnSBe . sin BnBaS . sin BnBeBa
Bedingung;: 1 =
sin BnBeS . sin BnSBa . sin BnBacSe
BnSBe = 80 46 8,782
BnBaS =¡=46 11 12,763
BnBeBa =16 28 45,212
(18)+ (19) BnBeS =31 38 44,836 - (24)+(26)
(3 2 ) + (34) BnSBa = 63 23 24,716 + (18) — (20)
(25) + (26) BnBaBe = 25 30 45,837 — (3 2 ) + (33)