Full text: Die Algebra (Theil 2)

174 
nut 
Dies in (2) subftituirt gibt -i-—oder 
rn 
a 1 Hh6 2 
Aufgabe 37. Halt man die vorige Bezeichnung bei; 
so ist 
(1) me+me*-\-me b + 
(2) rn + me 2 -f- me A 
ot>er me+7ne 3 +me ! 
. . . . +mr'‘ — 
.... +me 2 "‘ 2 = 6. 
. .. . +me 2 ' 1 ' 1 =: 
(2)—(1) gibt 6 — Dies in (2) substituirt gibt 
v 
a 2 
. + 
lln.l)— ' 
oder 
6 2 " 
— 1 
— 1 
m 
oder 
.2/, , 
■h 2n 
also rn 
a 2 h 2n - 2 — h 2n 
(a 2 —h 2 )h 2»- 1 
m 
«2» __ 
Aufgabe 38. Das Product der Mittlern Glieder fey 
— p. Dann sind 
« —1/( « 2 —4p) 
die Mittlern Glieder , 
— 4p) 
| (g — — 4p])* 
2(«+l/[« 2 4p] ) 
(a + l/O*—4p])* 
2(a— l/[« 2 — 4p ])
	        
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