Full text: [Höhere Arithmetik] Theorematis arithmetici (2. Band)

Beispiel 
m = + 3 — 2 i 
M = — 1 — 6 i 
li = +9 + 20» 
+ 4+13» 
+ 38 + 31»’ 
+ 1 
— 1 
—(— 5 —(— 7 i 
+ 29+11» 
0 
+ 0 
—J— 6 —(“■ i 
+ 20— 9 i 
0 —i 
— 3 
+ 10+14» 
+ 58 + 22» 
+ 1 
+ 1 
+ 11+ 8 i 
+ 49+ 2 i 
+ 1 
— 1 
+ 12+ 2 i 
+ 40—18» 
+1 * 
+ 2 
+ 16 + 15» 
+ 78 + 13» 
+ 2 
— 0 
+17+ 9» 
+69— 7 i 
+ 1—• 
+ 2 
+ 18+ 3» 
+ 60 — 27» 
+ 1—•' 
— 2 
Decident 
X 
X 
20 4 
20rj 
20 y 
20F 
£ 
y 
Y 
20C 
20t] 
lOx 
20 X 
£ 
+ 1 
0 
6 
1 
— 9 
— 37 
— i 
0 
— l 
3 
2 
+ 13 
+ 9 
+ 1* 
+ i 
4 
4 
+ 4 
— 28 
— i 
— 2 
6 
4 
+ 26 
+ 18 
+ 1 
+ 2 
2 
7 
+ 17 
— 19 
— i 
— 3 
9 
6 
+ 39 
+ 27 
+ 1 
+ 2 
+ 1 
10 
5 
— 5 
— 65 
— i 
+1 
— 1 
2 
8 
+ 22 
+ 46 
+ 1 
+ 2 
8 
8 
+ § 
— 56 
+ i 
+ 4 
— 3 
(+0 
y 
X 
«C 
9 Tj 
9x 
97 
£ 
X 
Y 
9 i 
9t] 
9 y 
9 X 
£ 
0 
+ 1 
3 
2 
+ 13 
— 20 
+ 1 
+ 1 
— 1 
l 
3 
H - 7 
+ 17 
— 1 
+ 1 
+ 2 
0 
3 
+ 6 
— 3 
— 1* 
+2 
— 3 
4 
3 
+ 1 
+ 14 
+ 1 
II 
III 
F 
6 i 
6x 
Qy 
6X j £ 
X 
3 i 
3 y 
3X 
3F | , 
— 1 
+ 1 
+ 3 + 9o) 
— 2 
— l —F 
+ 1 
1 
— 2 
— 1 
— 6 9 (0 | — 1 
— 2 
+ 2 
+ 6 + 9(0 
— 4 
— 2 1 +1 
0(—1) 
1 
X 
V 
12 rj 
1 2x 
12 y 
1 2 F 
£ 
X 
V 
4 ij 
4 y 
4 X 
fi AB) 
0 
+ 1 
+ 20 + 20(0 
— 9 
— 37 
— 1 # 
+2 
+ 1 
— 1 
+ 4- 
— 20 (o 
fiAB) 
+1 
+ 2 
+ 3 
+ 5 
+ 24 + 20(0 
—|— 2 8 —(— 2 0 (o 
— 3 
+ 3 
— 39 
— 41 
+ F 
—1 
y 
6tj 
6 <27 
6X 
6 F 
-1(0) 
0 
i 2 |+13 
+ 9 
— 20 
45 
4 F | £ 
— 13 l+i 
£ 
“M
	        
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