NACHLASS. 
II. Wahre Distanz: 
\/ j( i x '- +(y' ■- vY) (i - i- — v - r'' + -—) j 
III. Geographische Lage: 
tangX 
r cos ^P — —j 
tang Converg. Merid. = "(l —tang j 
sin Converg. Merid. — sin X sin |P — 
tang i(P — ~ — i^) = 4-7(1— tang ± Converg. Merid. 
IV. Die umgekehrte Aufgabe: 
y = rsinXcoscj>.(l + ^) 
sin Converg. Merid. = ~ tang cj> 
= sinXsinc( i .(l+^ ; ) 
tang Converg. Merid. = tang X sin cp. 
[2-] 
Convergenz der Meridiane = c. 
tangr=f + ^)’+ T * T $‘... 
sec Y = 1 U + 
sin F = y ~ 
r 
tangX = 
1 l 
T 
TT 
tV 
(f)' 
+ ril 
(?) 
s 
cos | 
(-?) 
tang c = tang (P - ^ - -ä- (ij+ * (ij...) 
sin c = sin X sin . 
P-f-<p = J R, 
[Setzt man]