ANALYSIS. NACHLASS. 
314 
= 1 +kk * -A- 6 -Ä- 8 +A t0 .. 
= 1 : (1 — M’-f-Ä' 4 * * — Ä 10 
[4-] 
Es wird gut sein, anstatt k einzuführen 
[4] 
[5] 
X = 
k = 
a — b 
a -f- & ’ 
1 + XX’ 
X = Ä + Ä 3 + 2A- 5 +5* 7 +14* 9 + 42*"... = 1 ~ >/( g~ 4U ' ) . 
T = t + — 3X S + 10X 5 — 29X 7 + 73X 9 — 
-f- i 5 (2 XX — 13 X 4 66 X° — 27 7 X 8 -)- 1 00 7X 
+ (5 X 3 — 51 X 5 —3 5 2 X 7 — 1 932 X 9 —j— 
—(— i 9 (14X 4 — 196X 6 —}— 1720X 8 — II 665X 10 — 
-f- i 11 (42 X 5 — 750X 7 -f8010X 9 — 
-j-i 13 (132X c — 287lX 8 + 36 1 90X 10 — 
-f i l5 (429X 7 — 11 01lX 9 -f 
t = T— T 3 (X — 3X 3 4- 1 oX 5 — 29X 7 
4- T :i (X 2 — 5 X 4 4- 2 1 X° — 7 7 X 8 
io 
* 
[5 a] 
wenn 
[6] 
E excentrische Anomalie. 
[T] = (i 4-2XX + X 4 4-2X 6 + 2X 8 4-...)(w4-Xw~‘), 
u — cos E 4- i sin E, 
Hieraus 
t = M + X(«- , -w 3 ) + XX(-M + i< 5 ) + X 3 (-w- | + 2M 8 -« i 
+ X 4 (—M -s + 2u — 2M 5 + ii 9 )... 
wie auch 
log t = log u -j- X (u 2 — u*) + XX (— 4 m 4 4“ 4 m 4 ) "T* 
4- x 3 (4 w 9 — u ' -\-u~ —1 m 6 ) 4~ ^ * (— t ^ 8 H~ i u 
[7]