Full text: From Aristarchus to Diophantus (Volume 2)

474 DIOPHANTUS OF ALEXANDRIA 
The species of the first class found in the Arithmetica are 
as follows. 
1. Equation Ax A + Bx 2 + Gx + d 2 = y 2 . 
As the absolute term is a square, we can assume 
G 
y=2d X + d ’ 
or we might assume y = m 2 x 2 + nx + d and determine m, n so 
that the coefficients of x, x 2 in the resulting equation both 
vanish. 
Diophantus has only one case, x 3 — 3îc 2 + 3x + 1 — y 1 (VI. 18), 
and uses the first method. 
2. Equation Ax 4 + Bx 3 + Gx 2 + Bx + E = y 2 , where either A or 
E is a square. 
B 
If A is a square ( — a 2 ), we may assume y = ax 2 + —-- x + n, 
cc 
determining n so that the term in x 2 in the resulting equa 
tion may vanish. If i? is a square (= e 2 ), we may assume 
y — mx 2 + —x + e, determining m so that the term in x 2 in the 
2 c 
resulting equation may vanish. We shall then, in either case, 
obtain a simple equation in x.. 
3. Equation Ax 4 + Gx 2 + E = y 2 , but in special cases only where 
all the coefficients are squares. 
4. Equation Ax 4 + E=y 2 . 
The case occurring in Diophantus is ce 4 + 97 — y 2 (Y. 29). 
Diophantus tries one assumption, y = x 2 — 10, and finds that 
this gives x 2 = 2 3 o, which leads to no rational result. He 
therefore goes back and alters his assumptions so that he 
is able to replace the refractory equation by a? 4 + 337 = y 2 , 
and at the same time to find a suitable value for y, namely 
y = x 2 — 25, which produces a rational result, x = -\ 2 -. 
5. Equation of sixth degree in the special form 
x G — A x 3 + Bx + c 2 — y 2 . 
Putting y = x 3 + c, we have —Ax 2 + B = 2cx 2 , and 
B B 
x 2 = -j , which gives a rational solution if -. is 
-A + 2 c yl + 2 G
	        
Waiting...

Note to user

Dear user,

In response to current developments in the web technology used by the Goobi viewer, the software no longer supports your browser.

Please use one of the following browsers to display this page correctly.

Thank you.