Full text: On the value of annuities and reversionary payments, with numerous tables (Vol. 1)

ASSURANCES ON LIVES. 
15/ 
the annual premium is therefore (l—r), and since —p- is the 
single premium, this quantity divided by (1 + #™) is 
Mm 1 _ M m D,„ _ M m 
D ))t ' 1 +a m D m ' N m _, N m _i’ 
which is also the formula. 
Rule (1). The single premium is found by adding one to the present 
value of .the annuity on the given life or lives, multiplying the sum by 
the difference between unity and the present value of £l due at the end 
of one year, and subtracting the product from unity. 
Or, (2) Multiply the annuity by the annual interest,of ¿£l, subtract 
the product from unity, and divide by the amount of ¿£l in one year. 
By Davies’s method : 
(3) Divide the number opposite the age in column M by the number 
opposite the age in column D. 
Or, (4) Divide the number in column N opposite the age one year 
younger than the given life by the number in column D opposite the 
given age, multiply the quotient by the difference between unity and the 
present value of £l due in one year, and subtract the product from 
unity. 
To find the annual premium ; 
(1) Divide the single premium by the annuity on the given life or 
lives increased by unity. 
Or, (2) Divide unity by the present value of the annuity increased 
by unity, and from the quotient subtract the difference between unity 
and the present value of £l due in one year. 
By Davies’s method: 
(3) Divide the number opposite the age in column M by the number 
opposite the age one year younger in column N. 
Or, (4) Divide the number opposite the age in column D by that 
opposite the age one year younger in column N, and from the quotient 
subtract the difference between unity and the present value of £l due 
in one year. 
192. Construction of column M, Carlisle 4 per cent. 
<W- 10 H w .r 100 .r 5 = 1 X .01980004 X .82192711 = .016274190=M 10 < 
d m r m =(l m -l m )r m .r*= 2 X .01980004 X .85480419= .033850312 
.050124502 = Mi 0S 
d m r l0 Hl m -l m )r m .r 3 = 2 X .01980004 X .88899636=.035204326 
.085328828=M 10a 
2 X .01980004 X .92455621 = .036612500 
J21941328=M 10 ,
	        
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