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ON THE HIGHER SINGULARITIES OF A PLANE CURVE.
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equation P 1 P. 2 ...P a = 0: the last-mentioned equation breaks up into the equations
P t = 0, P. 2 = 0,... P a — 0 ; and selecting for example the equation P 2 = 0, this gives the
system P 1 = 0, P. 2 P 3 ... P a ^P 1 = 0, or since we require only the intersections at the
singular point, and AP X = 0 does not pass through this point, this may be replaced
by Pj = 0, P. 2 P 3 ... P a = 0. The complete system is thus (P x = 0, P 2 P 3 ... P a = 0),
(P2 = 0, P 1 P 3 ...P a = 0),...(P a = 0, P 2 P- 2 ... P a _i = 0); or, what is the same thing, we have
each pair (P r — 0, P s = 0) taken twice. To eliminate y from these equations, we have
merely to write P r — P g = 0, or, what is the same thing, we have £(P x , P 2 ... P a ) = 0,
£ denoting the product of the squares of the differences of the functions (P 1} P 2 ...P a ).
Suppose that any two partial branches P r = 0, P s = 0 intersect (according to the
above-mentioned definition) in p points; then P r — P s contains the factor xP, and hence
the product £(P ly P 2 ...P a ) contains as a factor x to the power 2Sp, that is, the
equation in x has 2Xp roots each = 0. Whence if 2p = \M, then the equation in x has
M roots each = 0, or the curve and polar have at the singular point M intersections,
that is M = 28' + 3k .
I have no complete proof to offer of the remaining equation k = a — 1, it was
obtained from the consideration of a particular case as follows. Consider the linear
branch y = AxP + ... , where the exponents are all positive integers, and taking the
axis of x to be the tangent, the least exponent p is greater than unity; if p = 2
there is at the origin no inflexion, if p — 3 there is a single inflexion, and generally
the number of inflexions is =p> — 2. Now it will presently appear that in line-coordi-
p
nates the equation of the branch is Z — A'X p ~ l , or replacing Z, X by the original
p
point-coordinates y, x the branch y = A'x p ~ l + ... has at the origin p — 2 cusps; but
in the branch in question we have a=p — 1, and the number of cusps is thus
= a — 1 ; this result is confirmed by other particular instances, and I assume in
general that we have k = a — 1; whence in the case of a simple singularity, or where
there is only one branch we have M = 2<f + 3k, k = cl — 1, or, what is the same thing,
8' =\ \_M — 3 (a — 1)], k=ol — 1. The reasoning is easily adapted to the case of a com
pound singularity.
I consider the branch
y + Ax p + Bx q + ... = 0,
(where it is assumed that the axis of x is a tangent to the branch, and therefore
that the lowest exponent p is greater than unity), introducing the coordinate z for
homogeneity, this becomes
yz~ Y + Ax p z~ p + Bx^z~i + ... = 0,
and I proceed to find the corresponding equation in line coordinates, taking these to
be X, Y, Z, we have
XX =pAx p ~ l z~ p + Bqx q ~ l z~ q + ...,
\Y= z~\
\Z = — yz~“ 2 — pAx p z~ p_1 — qBx q z~ q ~ 1 + ...,