WITH A 16-NODAL QUARTIC SURFACE.
159
[662
662]
>arently arbitrary
her on. I recall
its u, u', are*
3 which are odd
Pi, • • • , Q\ etc.,
stants, depending
ich are however
parameters: the
ear functions of
ns between the
ling 12 squares,
•e linearly inde
ed he seems to
m five squares.
deux variables
364—468, that
e exist sixes of
each of the
e three squares,
equations, and
by the following
Strahlensysteme
14
15
16
14
15
16
6
7
8
2
3
4
11
10
9
12
9
10
9
12
11.
In fact, to show that any four of the squares, for instance 1, 9, 13, 8, that is,
P 2 , P 2 2 , R 2 , R s 2 , are linearly connected, it is only necessary to show that the determ
inant of coefficients
a,
~/3,
~7,
8
a,
-¡3,
7,
- 8
7,
- 8,
— a,
/3
7,
8,
a,
/3
is = 0, or what is the same thing, that there exists a linear function of the new
variables (X, Y, Z, W), which will become = 0 on putting for these variables the values
in any line of this determinant: we have such a function, viz. this is
/3X + aY-8Z-yW,
or say
[1] (0, -S, -y)(X, r, Z, W).
This function also vanishes if for (X, Y, Z, W) we substitute the values
8, ~ V, ¡3, - a,
8, 7, /3, a,
which belong to 7, 6, that is, S 2 2 and S 2 respectively. It thus appears that 1, 9,
13, 8, 7, 6, that is, P 2 , P 2 2 , R 2 , R- 2 , S 2 , S 3 2 , are a set of six squares having the
property in question. I remark that the process of forming the linear functions is
a very simple one; ive write down six lines, and thence directly obtain the result, thus
1
a,
-/3,
~7,
8
9
a,
-/3,
7,
-8
13
7»
-8,
~ a,
/3
8
7,
8,
a,
/3
7
8,
~7,
A
— a
6
8,
7,
A
a
/3,
a,
-8,
-7:
viz. /3, a, 8, y are the letters not previously occurring in the four columns respect
ively: the first letter /3 is taken to have the sign +, and then the remaining signs
are determined by the condition that, combining the last line with any line above it
(e.g. with the line next above it /38 + ay — 8/3 — ya), the sum must be zero.
We find in this way, as the conditions for the existence of the 16 sixes respectively,
[1]
(/3,
a,
-5,
-7)№
Y, Z,
W) = 0,
[2]
(«>
-/3,
- 7>
S)(X,
Y, Z,
W) = 0,
[3]
(«>
/3,
~ 7>
- S)(X,
Y, Z,
W) — o,
[4]
(/3,
- a,
- 8,
y)(X,
Y, Z,
W) = 0,