400 
A TENTH MEMOIR ON QUANTICS. 
$4 = Cl 3 .0 
+ a 2 (6 (0c + 0) 4- 6° (Oc 3 + 0c 2 + Oc + 0)} 
+ a (6 3 .0 + 6 2 (Oc 2 + Oc + 0) + b (— 9c 4 + 36c 3 — 54c 2 + 36c — 9) 
+ 6° (36c 5 - 171c 4 + 324c 3 - 306c 2 + 144c - 27)} 
+ a° (Oc + 0) + b 3 (7c 3 - 21c 2 + 21c - 7) + 6 2 (- 39c 4 + 135c 3 - 17lc 2 + 93c - 18) 
+ b (66c 5 - 243c 4 + 333c 3 - 201c 2 + 45c) 
+ 5° (- 27c 7 + 101c 6 - 141c 5 + 87c 4 - 20c 3 )} : 
which for с = 1 becomes = 0. 
It follows that, for c — d = e=f= 1, the value of the covariant S is =2(6 
which might be easily verified.