Full text: The collected mathematical papers of Arthur Cayley, Sc.D., F.R.S., late sadlerian professor of pure mathematics in the University of Cambridge (Vol. 10)

[652 
71 
= r 2 ) the 
radius r. 
die values 
r — 1, we 
‘S to \nt, 
)tained by 
3) cos 26; 
^ 2 ] ON A SEXTIC TORSE, 
or, what is the same thing, it is 
rV - 2e (3tf- - 2) (a? -,/)+ (.V - 2)‘ - (4 (»•« - 1)* + (3r‘ - 2) a ) = 0, 
viz. the term in { } being ?- 4 (4?’ 2 -3), this is 
r 4 * 2 - 2 z (3 r 2 - 2) (x 2 - if) + (Sr 2 - 2) 2 - W (4r 2 - 3) = 0, 
or say 
0 2 O 2 + iff - 2 z (Sx 2 + 3 if - 2) (x 2 - if) + (Sx 2 + Sif - 2 ) 2 - 4 x>if (4# 2 + 4 f - 3) = 0. 
This may also be written 
{2 (x 2 - if) - 3 x 2 - Sif + 2j 2 + 4 ay (z 2 - 4a? - 4 y 2 + 3) = 0, 
a form which puts in evidence the nodal curves 
x = 0, xif = — 3f + 2, and y = 0, zoo 2 — Sx 2 — 2. 
It shows also that the quadric cone 2 2 - 4x 2 - 4y 2 + 3 = 0 touches the surface along 
the curve of intersection with the surface 2 (x 2 — y 2 ) - 3 (x 2 + y 2 ) + 2=0. This is, in 
fact, the curve of maxima and minima of the cylindrical sections, viz. reverting to the 
form f(4r 2 -S)cos(26 +/3), or, if for greater clearness, attending only to one sheet 
of the surface, we write it z = f(4r 2 — S) cos (26 —/3), we have a maximum, z = f(4r 2 — S), 
for 26 = ft (or 27r + /3), giving 
Sv 2 — 2 3r 2 — 2 
cos 20=cos /3, = —, = —-—: 
r 2 y(4?’- — 3) r 2 z 
and a minimum, z = — f(4r 2 — 3), for 2#=7t + /3 (or 37r -f ¡3), giving 
3r 2 — 2 3r 2 — 2 
cos 26 = — cos /3 = — 
r 2 V(4r 2 - 3) ’ 
r 2 z 
viz. the locus is z 2 = 4(r' 2 — S), z(x 2 — y 2 ) — 3^—2; and for # = \/(4r 2 — 3)cos(20 + /3) we 
find the same locus, viz. the equations of the locus are 
z 2 — 4# 2 — 4y 2 +3=0, z(x 2 — y 2 ) — Sx 2 — 3 y 2 + 2 = 0, 
as above. 
To put in evidence the cuspidal edge, write for a moment ^—z — a? + y 2 , the 
equation becomes 
{? (x 2 - y 2 ) + (r 2 - 1) (r 2 - 2) - 4 x 2 y 2 } 2 + 4 x 2 f f 2 + 2£(x 2 - if) + (r 2 - 1) (r 2 - 3) - 4 x 2 y 2 } = 0 ; 
viz. this is 
^r 4 + 2£(# 2 - y 2 ) (r 2 -1) (r 2 - 2) + (r 2 - l) 2 (r 2 - 2) 2 - 4x 2 y 2 (r 2 - l) 2 = 0, 
or writing the last term thereof in the form 
- {r 2 - (x 2 - y 2 f \ (‘r 2 - l) 2 , 
and then putting r 2 — 1 + U, the equation is 
£ 2 (1 + 2 U+U 2 ) + 2£U(U- 1) 0v 2 - if) + U 2 (U-If - U 2 {(U+ l) 2 - (a? - y 2 ) 2 } = 0; 
viz. this is y*)Y + 2U{? + SU(x 2 - f) - 2 U 2 } + ?U 2 = 0,
	        
Waiting...

Note to user

Dear user,

In response to current developments in the web technology used by the Goobi viewer, the software no longer supports your browser.

Please use one of the following browsers to display this page correctly.

Thank you.