114
THE APPLICATION OF ALGEBRA
n % . U + 1
2/1 — 2
24
2 n l . n \ \ . n — 1
12
12
Therefore
n 1 . n
— 1 . e l
6 Y and e —
—- ] is known
12
✓
u z / vir 1
12«c— 12Ä*
; whence x
2
** 1 i . e
Example. Let the given number of terms be 6, their
sum 33, and the sum of their squares 199; then, by
writing these numbers, respectively, for //, b, and c, we
shall have e — \ \ whence x — 2, and the required
numbers 3, 4, 3, 6, 7, and 8.
/
PROBLEM LXI II,
Tiro post-boys A and B set out, at the same time, from
two cities 500 miles asunder, in order to meet each other :
A rides- 60 miles the first day, 55 the second, 50 the third,
and so on, decreasing 5 miles every day : but B goes 40
miles the first day, 45 the second, 50 the third. §c. in
creasing 5 miles every day; now it is required to find in
what number of days they will meet ?
In order to have a general solution to this problem,
let the first day’s distance of the post A be put = m,
and the distance which he falls short each day of the
preceding — d; also the first day’s distance of the post
B - p, and the distance which he gains each day = e ;
and let a: be the required number of days in which they
meet: then the whole distance travelled by A will be
expressed by the following arithmetical progression,
m + m — d + m — 2d + m — 3d, &c. and that of B by
p -f p -f e T p + ' 2e + p + 3e, &c. where each pro
gression is to be continued to x terms. But the sum of
the first of these progressions [by Sect. 10, Theor. 4.) iszr
0
x x x— 1 x e
therefore these two last expressions, add-
2