28o 
•/ 
Achter Abschnitt, 
VSN ■§ = 2 s\ -f- r + r i ic >v* Man di- 
V. 5-S 3 S-5 i y 
vidire also 2 durch 5, so wird 
2 
T 
= A = 
o, 40000000000000000000 
1 
IT 
A = B =. 
I600000000000000000 
T 
77 
B == C = 
640000000000000000 
r 
77 
C = D = 
2560000000000000 
z 
17 
D = E == 
102400000000000 
T 
IT 
E = F = 
4096000000000 
I 
17 
F =G = 
I6384OOOOOOO 
I 
17 
G — H = 
655360OOOO 
I 
IT 
H = I — 
262I44OOO 
I 
17 
I = K = 
IO485760 
T 
17 
K = L = 
419430 
i 
IT 
L = M = 
16777 
i 
77 
M= N — 
67I 
T 
77 
11 
0 
11 
z 
27 
i 
77 
II 
II 
0 
s 
( ' - ‘ - 
Hier-