Practical use of of Block Ad justment for Aerial Triangulation by mears 
13 
III. Computation 
In the case of 4 courses, we calculated all strips in following four steps, for 
the capacity of our computer NEAC--2203 is only 2000 words. 
1. To type and puch out the coefficients for the least squares computation 
on 13 elements. 
To type and punch out the solution of the simultaneous equations on 13 
elements. 
To type out the residuals of control points used for calculations and 
differences between the tie points. 
To type out the coordinates of calculated correction points. 
In the case of 2 courses, we can calculate 1.2 and 3, in one time. 
In the case of 4 courses, the number of control points and tie points available 
for calculation are about 15 and 20, respectively. 
2. 
3. 
4. 
ey 
Table II. 
NAME 
VH 
VX 
VY 
m 
m 
m 
C1-34T 
0 
000.66 
0 
000 
14 
0 
001.21^ 
C1-36T 
-0 
000.13 
0 
000 
28 
-0 
000.11 
C1-38T 
—0 
001.16 
0 
001 
19 
-0 
000.24 
C1-40T 
0 
000.95 
0 
000 
94 
-0 
000.09 
C1-42T 
0 
000.57 
0 
000 
41 
0 
000.20 
C1-43T 
-0 
000.64 
0 
000 
99 
0 
000.15/ 
C2-32T 
0 
000.41 
0 
001 
02 
0 
000.06\ 
C2-31T 
-0 
000.42 
0 
000 
98 
0 
000.39 
C2-29T 
0 
000.75 
0 
001 
16 
-0 
000.30 
C2-27T 
-0 
000.97 
0 
000 
74 
-0 
000.02 
C2-25T 
0 
000 
77 
-0 
000.60/ 
C3-01T 
0 
000.58 
-0 
000 
23 
0 
000.02s 
C3-03T 
-0 
000.46 
-0 
000 
09 
0 
000.21 
C3-05T 
-0 
000.84 
-0 
000 
35 
-0 
000.53 
C3-07T 
0 
000.08 
-0 
000 
63 
-0 
000.19 
C3-09T 
0 
001.07 
-0 
000 
42 
-0 
000.18 
C3-10T 
-0 
000.69 
-0 
000 
50 
-0 
000.09 
C3-11T 
-0 
000 
31 
0 
000.62/ 
005-P3 
-0 
000.01 
0 
000 
22 
-0 
000.86\ 
067-H0 
0 
000.75 
0 
000 
03 
-0 
000.41 
007-P2 
-0 
000.34 
0 
000 
28 
0 
000.23 
059-H0 
-0 
000.02 
-0 
000 
17 
0 
000.23 
038-P2 
0 
000.02 
0 
000. 
65 
-0 
000.66/ 
013-H0 
0 
000.03 
0 
000 
48 
-0 
000.18\ 
011-PI 
-0 
000.07 
-0 
000 
79 
0 
001.00 
040-H0 
0 
000.55 
015-H0 
-0 
000.02 
-0 
000. 
98 
0 
000.45/ 
017-P2 
0 
000.22 
0 
000. 
56 
0 
000.31S 
007-P2 
-0 
000.02 
-0 
000. 
23 
-0 
000.56/ 
021-H0 
-0 
000.00 
-0 
000. 
76 
0 
000.46\ 
010-H0 
-0 
001.09 
-0 
000 
74 
-0 
001.10 
008-P 2 
0 
000.37 
-0 
000 
11 
0 
000.28 
007-P2 
0 
000 
34 
0 
000.26/ 
Differences of tie points between the 
C1-C2 
Differences of tie points between the 
C2-C3 
Differences of tie points between the 
C3-C4 
Residual errors of control points of Cl 
Residual errors of control points of C2 
Residual errors of control points of C4 
IV. Example 
An example of above method in case of 4 courses is as follows: 
1. Camera that used for the photograpy is RC5 (Aviogon). Scale of photo, 
is about 1/12500 
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Virginia; (7) Army Map Service, Washington, D. C.; (8) U.S.