With the equation (10), we can gain
1 2
door (11)
a m
IN, - k| ;
As — =a-1<0.005, we can gain
1
==> 0.9831 (12)
a
With the equation (11) and (12), we can gain
1.9702
AR FT (13)
T
With keeping two digit of decimals, indicated from the
monotonicity of N and m ,derived from above deduction, the
-k
condition which makes Mk < 0.005 tenable is 4, > E ,
cT
1
i.e.
i3 24 (5 sinit CT
sin) C) sin) 1g
> (14)
Eo OR CE
2 2h 72k
1
The above equation is very complicated. we need to get its
simplified form for convenient calculation. Here, the least
squares curve fitting method of 1000 uniform sampling points
(m,k,) obtained by the equation (14) is used to derive the
simplified formulas of &, and m. As up to now, the highest
precision in point cloud data processing of terrestrial laser
scanning is 0.01 folds laser beamwidth(Zhang Yi, 2008), and
the maximum angular quantisation of different scanner is 2.08
folds laser beamwidth(GIM, 2010). Therefore, we define that
m € [0,2.5] and fitting precision is 0.005. Then, we can get the
relationship graph of 4, and m (Fig.2) and the fitting formulas
of k is
k =a +b-(m—g) +h (15)
where a = 30.8136
b, =41.03034
g, = 0.0008
h, = 0.006
From the equation (15), we can see that the relationship graph
of k, and m is hyperbola, and the fitting errors of the equation
(15) and m is Fig.3. From the plot of Fig.2, we can see that
fitting errors is less than 0.005 when m > 0.01. so we can think
that the equation (14) is approximately equaivalent with the
equation (15).
International Archives of the Photogrammetry, Remote Sensing and Spatial Information Sciences, Volume XXXIX-B3, 2012
XXII ISPRS Congress, 25 August — 01 September 2012, Melbourne, Australia
Kk,
16
14 -
12
10 -]
8
6 4
0 08 d 26 UM
Figure 2. The rationship curve graph of k, and m
0.0006 —
0.0004 —
0.0002 —
0.0000 —
-0.0002 +
-0.0004 1 1 + T T T T T
0.0 0.5 1.0 15 2.0 2.5m
Figure 3. The rationship curve graph of fitting errors &
(equation (15)) and m
3.2 The Relationship & Simplified Formula of k, And m
With the equation (6), (7) and N=1 , we can gain the
relationship of k, and m that is
ann sint)
2 aa do
Eu tinc)
2 2 2
where 0X k, < 0.545
0€ m € 0.545
The above equation is still very complicated. Its simplified form
can be derived through the same method as above. we can get
the relationship graph of k, and m ( Fig.4) and the fitting
formulas of &, and m that is
k, 2 a, -b,-(m+g,) + j,-m—h, (17)
where a, = 0.35426
b, =0.99264
gj -0.0521
J, =0.085793
h, =0.047672
Fro!
ellij
Fig.
less
app
3.3
Wi
rel:
Th
as
wh
Fr
hy