Fig. 3 Result by Maximum Percentage Method 
Fig. 5 Result by Element Ratio Matching 
  
C 
<+ 
vn 
= 
= 2 
o - 
= o 
- = 
= [5] E^ 
© = 
RE £ ed 
2 s © 
E o = 
= or - 
= ca o 
5 z 2 
= = > 
gon — o 
3 = 2 
= o 
2 > 
> 
2 2 2 
Ja 
= = = 
= = = 
© N N 
S? D 
Su e 
oN -—- co 
20 : . 
= uo e 
us E.