]J. Die Sclilesisch-Posenscke Kette.
509
f
S 2*
Annahme: Schwarze Berg 0° 0' 0"
Trebchen
49
38
52
+
A
Kobelnik
74
17
1
+
B
Guzdzin
106
45
5
+
C
Chmilinko
145
10
44
+
D
Tarnowo
181
51
33
+
E
Kicin
237
0
39
+
F
Schroda
307
6
18
+
G
End gleich ungen:
+ 5,602 = + 19,398 A — 1,650 B
4- 11,590 = + 17,683 B
-f 14,570 =
— 13,421 =
— 5,490 =
— 11,131 =
+ 11,044 =
(a)
— 2,202 0 — 1,869 D — 3,269 E — 2,769 F — 3,436 Q
— 1,917 C — 1,917 D - 6,317 E — 2,983 F — 1,650 0
+ 18,298 0 — 2,869 D — 3,702 E — 1,536 F — 2,036 G
+ 18,464 D — 3,202 E — 1,869 F - 1,869 G
+ 29,898 E — 4,102 F — 4,269 G
+ 17,898 F — 2,269 G
+ 19,064 G
(6)
+ 5,602 = + 19,398 A — 1,650 B
+ 12,066 = + 17,543 B
+ 16,653 =
— 8,337 =
+ 2,049 =
— 6,809 =
+ 12,082 =
— 2,202 C — 1,869 D — 3,269 E — 2,769 F — 3,436 G
— 2,104 C — 2,076 D — 6,595 E — 3,219 .F - 1,942 G
+ 17,796 C — 3,330 D — 4,864 E — 2,236 F — 2,659 G
+ 17,415 D — 5,207 E — 2,935 F — 2,927 G
+ 23,982 E — 7,268 F — 7,180 G
+ 13,933 F — 6,118 G
+ 12,515 G
A = + 6^704
B = -f 1,025
C = + 1,128
D = — 0,221
E = 4- 0,355
F = — 0,065
G = + 0,965