414 
Netzausgleichung. 
LI. Velbert — Remscheid — Rade. 
Velbert = 18 9 17,,497 — (33) + (34.) 
Remscheid =116 o 43,454 + (88)— (91) 
Rade = 3 5 5° o,^59 — (95) + (9 6 ) 
Summe =180 o 1,210 
i8o° + £ = i8o o 0,716 
o = + 0,494 — (33) + (34) + (88) — (91) — (95) + (96) 
LII. Remscheid — Birkhof — Velbert — Rade — Heck. 
Bedingung: 1 = 
sin 28.29 . sin 34.35 . sin 95.96 . sin 87.81 
sin 86.87 . sin 27.28 . sin 33.34 . sin 94.95 
28.29 = 38 5 3,929 —(28)+ (29) 
34-35 = 43 3* 32,005 — (34) + (35) 
95.96 = 355° 0,259 — (95) + (96) 
87.81 = 31 4 26,996 + (81) — (87) 
9,790 1598.07— 26,87 (28)+ 26,87 (29) 
9,838 1492.16—22,16 (34) + 22,i6 (35) 
9f7 6 7 4753-09 — 29,16 (95) + 2 9/i6 (9 6 ) 
9i7 iz 7735- 66 +34,94(8x) —34,94(87) 
9,108 5578.98 
9,108 5586.94 
— 7.96 
86.87 = 83 52 17,7x6 — (86) + (87) 
27.28 = 15 59 25,042 — (27) + (28) 
33.34 = 28 9 17,497 —(33)+ (34) 
94.95 = 8327 3,162 — (94) + (95) 
9,997 5109.43— 2,26(86)+ 2,26(87) 
9,440 0813.01 — 73,48 (27) + 73,48 (28) 
9,673 8097.53 — 39,34 (33)+ 39,34 (34) 
9,997 *566.97 — 2,42(94)+ 2,42(95) 
9,108 5586.94 
0,0796 + 0,7348 (27) — 1,0035 (28) + 0,2687 (29) + 0,3934(33) — 0,6150(34) 
+ 0,22r6 (35) + 0,3494 (81) + 0,0226 (86) - 0,3720 (87) + 0,0242 (94) 
— 0,3158 (95) + 0,2916 (96) 
Uli. Velbert — Balverwald — Rade. 
Velbert = 32 o 21,949 — (32)+ (33) 
Balverwald = 28 15 37,176 — (39) + (40) 
Rade =119 44 3,811 +(92) — (96) 
Summe =180 
i8o°+ £ = 180 
2,936 
2,264 
o, 6 72 — (32) + (33) — (39) + (40) + (92) — (96)