176 
Netzausgleichung. 
9,982 5528.9 — 6,09 (1) + 6,09 (3) 
9,874 8302.4—18,59 (21) + 18,59 (22) 
9,97^ 7876;2 — r 4,39 ( 6 ) + *4,39 ( 8 ) 
9,774 1707.5 
9,774 1708 1 
— 0.6 
0 = — 0,030 — 0,3045 
- °, I 995 
9,8770364.5 — 18,38 (7)+ 18,38 (8) 
9,998 0095.8 — 2,02 (2) + 2,02 (3) 
9,899 1247.8 + 16,19 ( l8 ) — 9 ( 2I ) 
9,774 1708.1 
(0 -h 0,1010 (2)+ 0,2035 (3) —0,7195 (6)+ 0,9190 ( 7 ) 
(8) — 0,8095 (18) — 0,1200 (21) + 0,9295 (22) 
VIII. Belchen — Sausheim — Basis nördlich. 
O / 11 
Belchen = 31 38 44,836 — (24) + (26) 
Sausheim = 80 46 8,782 — (18) + (19) 
Basis nördlich — 67 35 7,431 — (5) + (6) 
Summe = i8q o 1,049 
i8o°+£ = i8o o 1,598 
o = — 0,549 — (5) + (6) — (18) + (19) — (24) + +6) 
IX. Ballon — Sausheim — Basis nördlich. 
O / 11 
Ballon = 46 11 12,763 — (32) + (34) 
Sausheim — 63 23 24,716 + (18) — (20) 
Basis nördlich = 70 25 23,291 — (6) + (9) 
Summe =180 o 0,770 
i8o°+t=i8o o 1,073 
o = — 0*303 — (6) + (9) + (18) — (20) _ (32) + (34) 
X. Ballon — Belchen — Basis nördlich. 
Ballon = 25 30 45,837 - (32)+ (33) 
Belchen = 16 28 45,212 — (25) + (2b) 
Basis nördlich = 138 o 30,722— (5)+ (9) 
Summe =180 o 1,771 
i8o° + f=i8o o 1,433 
0 = + °,33 8 — (5) + (9) — ( 2 5) + (* 6 ) — (l 2 ) + (> 3) 
XI. Basis nördlich — Belchen — Sausheim — Ballon. 
sin BnSBe . sin BnBaS . sin BnBeBa 
Bedingung;: 1 = 
sin BnBeS . sin BnSBa . sin BnBacSe 
BnSBe = 80 46 8,782 
BnBaS =¡=46 11 12,763 
BnBeBa =16 28 45,212 
(18)+ (19) BnBeS =31 38 44,836 - (24)+(26) 
(3 2 ) + (34) BnSBa = 63 23 24,716 + (18) — (20) 
(25) + (26) BnBaBe = 25 30 45,837 — (3 2 ) + (33)