Maydenberg. 
Beobachtungen. 
119 
Polliöhe aus den Circummeridian-Beobachtungen: 
Morgen-Beobachtungen: cp = 48° 52' 9 f 52 
Abend-Beobachtungen: cp = 48 52 9*99 
Mittel: cp = 48° 52' 9-76±O r 17. 
(72 Doppeleinstellungen) 
b) Beobachtungen im Meridian. 
V. Beobachtungen und Reduktion der Meridian-Zenithdistanzen. 
Angenommen: cp = 48° 52' 10' 
1891. Juli 1. p, m. C = 60 48 35 
Stern- 
Wegen 
Libelle und Run 
korrigierte Kreis 
ablesung l 
S 
oder 
180° — 
0 
B 
sin z 
Bestimmungs-Gleichungen 
Fehler 
Nr. 
Name 
Größe 
Kreistage West. 
221 
[cp Herculis] 
4-0 
57° 
9’ 
48 r 7 
H- 
45° 13' 
19 v 9 
3 V 3 
0 V 063 
Acp — AC — 0-083 h + 0 J 5 = 0 
— 2'-'10 
222 
§ Ophiuchi 
3-0 
8 
32 
45-5 
— 
3 24 
52-2 
1' 7-1 
0-791 
Acp - AC —0-791 0 4-5-6 = 0 
4-2-64 
228 
e Ophiuchi 
3-3 
7 
31 
59-3 
— 
4 25 
40-1 
1 9-7 
0-802 
Acp — AC — 0-802 b 4- 4-7 = 0 
4- 1-73 
472 
19 Urs. min. 
5-8 
88 
5 
13-1 
4- 
76 9 
13 0 
26-9 
0-458 
Acp — AC 4-0-458 & 4-2-0 = 0 
— 0-34 
Kreistage Ost. 
224 
x Herculis 
3-3 
63° 
6' 
15-7 
_J_ 
46° 34' 
27 v 8 
2 ? 1 
0 ? 040 
Acp4-AC — 0-040 b —0-6 = 0 
4- l r 05 
473 
[<« Herculis] 
5-0 
95 
23 
5-3 
4- 
14 17 
3-8 
35-9 
0-568 
Acp + AC — 0-568 b 4- 0-0 = 0 
4-1-38 
226 
Yj Draconis 
2-6 
47 
55 
11-2 
—h 
61 45 
45-0 
11-9 
0-:23 
Acp + AC 4- 0-223 0 4-0-7 = 0 
4-2-48 
228 
^ Herculis 
2-3 
87 
56 
41-6 
4- 
21 43 
39-1 
26-7 
0-456 
Acp + AC — 0-456 b — 2-4 = 0 
— 0-96 
229 
A Draconis 
5-0 
40 
40 
45-1 
69 0 
20-1 
19 1 
0-344 
Acp + AC 4-0-344 5 — 1-1 = 0 
4-0-74 
230 
o Herculis 
4 1 
67 
0 
57-8 
4- 
42 39 
46-4 
5-7 
0-108 
Acp 4- AC — 0-108 b — 4-9 = 0 
— 3-29 
476 
[Gr. 2373] 
6-0 
32 
1 
22-3 
4- 
77 39 
52-8 
28-6 
0-482 
Acp -+- AC 4-0-482 0 — 1-5 = 0 
4-0-41 
231 
[C Herculis] 
2-6 
77 
52 
27-8 
4- 
31 48 
4-0 
16-0 
0-293 
Acp4-AC — 0-293 6 — 2-8 = 0 
— 1-28 
232 
yj Herculis 
3-1 
70 
32 
48-1 
+ 
39 7 
50-1 
8-9 
0-169 
Acp 4- AC — 0-169 b — 2-1 = 0 
— 0-52 
Kreistage West. 
477 
Gr. 2377 
5-0 
68° 
54' 
56 r 8 
4- 
56° 58' 
40 v 4 
7 V 4 
0 ? 141 
Acp — AC 4- 0-141 6 — 1-2 = 0 
4-3-70 
478 
49 Herculis 
6-0 
27 
6 
30-2 
4- 
15 9 
26-0 
34 8 
0 • 555 
Acp — AC — 0-555 6 4-4-4 = 0 
4-1-56 
233 
x Ophiuchi 
3-3 
21 
29 
53-2 
4- 
9 32 
40-1 
42-7 
0-633 
Acp — AC — 0-633 5 4-5-4 = 0 
4-2-52 
234 
e Herculis 
3-3 
43 
1 
59'3 
-1- 
31 5 
15-0 
16-7 
0-305 
Acp — AC — 0-305 b 4- 2-6 = 0 
- 0-12 
235 
£ Urs. min. 
4-3 
94 
8 
52-1 
4- 
82 13 
1-3 
34-3 
0-550 
Acp — AC 4- 0 • 550 b 4~ 0 • 1 = 0 
— 2-19 
Normalgleichungen: 
18-0. Acp+ 0-0 
• AC- 
2-585 b 4- 9 4 = 
= 0 
0-0. Acp + 18-0 
AC 4- 1*415 b — 
38-8 = 
= 0 
o 
•585. Acp + 1-415. AC 4-3-665 0 — 
5-992 = 
= 0 
Auflösung: 
Acp = — 
0 • 45 Gewicht 16 • 1