306 
ANALYSIS. NACHLASS. 
Wir haben folglich 
(£8 + £ s )m-h(£ + e 4 )w = (e 4- £ £ -f- £ 3 -f 0 ( J +2a;+ 2£ 4 +2r ) H ), 
— (££ + £ 3 )?w + (e + e 4 )w = (e — £ £ — £ 3 + £ 4 ) ' ( 1 + 2a? 5 + 2ar°+ 2^ 4 -} ), 
also 
(1 2o; 4 4-2^ 9 -| ) + (£ — ££ — e^Oi 1 +2ar i + 2a; 20 -f...) 
[»•IMt« 10 ! 8 
— 2 (££-j-£ 3 ) m 
(l + 2^+2^ 4 + 2ir 9 4 .) — (£ — ££ —£ 3 + £ 4 )(l +2^ + 2^° 4 ) 
nf , i\, [as*] [a?] [£C 10 ] 2 
— 2 \®+® ) W [iC^tiC»]^ 20 ] 
Also Product 
_ _ 4 r #yi 
* [ic B ][a5*°] L ' J ’ 
fl I o r L \ 2 5 fi 4- 2iC 5 4- 4 — — 4 .Izg!—L+ .4°. 1 -a:1 °.... M 2 14_T 
( 1 - r 2it + .--j — i ] — 4 1-a; 1+asa . l _ x n [ x *Y[x*»Y 
[x l f 
[xxY 
[15. 
Die Siebentheilung führt auf folgende Gleichung 
b 
A 
B 
I l-2x + 2x l Y 
\1 + 2ic + 2a; 4 + -- •) 
1 -\-2x 7 -\-2x 23 ■ 
l-\-2x-\- 2x l -\- ■ 
1 — 2x 7 -f- 2a: 28 — • 
l + 2a? + 2» 1 +' 
[*)] Bedeutet salvo calc[uli] err[ore] 
5 PP —pp = 4 \/ppq 5 \- 
5QQ - qq 
r \5 PP 
2y «A 
v 2 
5PP— 
5^0 
-PP _ 
-22