tions is very small, resulting from a limites
size of the hologram plate, and substantial
errors would result. Use of more than one
hologram is not feasible because a continuous
observation of the fringe shifts at a point
of interest is not possible as one moves from
observation point on one hologram to the next
hologram. An alternative to this is to gen-
erate an overdetermined set of linear simul-
taneous equations relating the fringe shifts
to three unknown components of displacement;
one equation for each change in the direction
of observation. Therefore, we perform multi-
ple observations (more than three) of the
holographically reconstructed image. For
each observation, we compute the sensitivity
vector X and also, we determine the corre-
sponding fringe shift n. From multiple views,
we obtain à set of equations of the form of
Eq. 7 (one equation for each view), with the
vector d eommon to all, which ean be combined
into a Single matrix equation
[K] (d) = (8) , (9)
where the elements of the rectangular r x 8
matrix [K] are differences between components
of the corresponding observation vectors.
Finally, we multiply both sides of Eq. 9 by
the transpose of the rectangular matrix [X];
this procedure decreases the rank of the rec-
tangular matrix [X] to a square, three by
three, matrix and yields the solution of the
displacement vector d which has the least-
Squares error, =
« » [I] (]] (1 (»)
Expanding Ed.
(10)
10, we obtain
I
m=.
r im el, r l,m l,m Lm Lm of r Lm Im
d,| | XAKo,AKo, YAKo, AKo, DAKo, AKo, | YQ AK,
m=2 m=2 2 m=2
r gm. bm. Lo im. bm Qo bm. hm T Lm hm
dy p AK», 2D, AK2, Sz, Kp, m AK,
C Vm. . bm L lm. im rh
AK, AK AK» AK Q
25 er, = 2,72. 2
m
l,m
r l,m lm m
d; 28 Kp z AK, AK 2;
(11)
where the elements of the square matrix are
defined as
l,m m |
= KT — 12
AKT eK KS ois (12)
hm -_ m |
ly |
AK, = Ke,” Ka, (14)
The components of the observation vector a
entering Eqs 12-2! are as defined in Eq. 2.
The least-squares method, described in the
foregoing discussion, can be used as follows.
Decide as to the number of observations r to
be made through a single hologram, e. g
nine as shown in Fig. 6.
oy
Determine the di-
24
rections of the observation vectors using, e.
g., Eq. 3. Assume the sign convention for
fringes moving across the point of interest
on the surface of the object. Obtain fringe
shifts while moving from an observation
through the center of the hologram to obser-
vation through any other point, one at a time.
Compute the components of the observation vec-
tors and substitute them into Eqs 12-14 and
these results, in turn, into Eq. 11 which must
be solved for the Cartesian components of the
displacement vector d.
A computer program for the solution of Eg. 11
was developed [3] and used in the present
Study.
DISCUSSION OF EXPERIMENTAL RESULTS
The maximum tensile load applied to the tested
airfoil produced a displacement in excess of
1/4 mm. Obviously, the displacement of this
magnitude is too great to be successfully re-
corded by one double-exposure hologram; it
would result in fringe patters of frequencies
too high to be resolved using standard proce-
dures and construction of special facilities,
for this purpose, would be impractical.
Therefore, in order to circumvent this prolem,
the maximum tensile load, required in these
tests, was applied in increments of approxi-
mately 200 lbs each and for each increase in
the applied load a double-exposure hologram
was recorded. This resulted in a total of
ten holograms, one for each increment in the
tensile load from zero lbs to 2,061 lbs. Now,
the fringe patterns observed during recon-
struction of these holograms were very dis-
tinct and, therefore, easy to resolve. A
typical fringe pattern due to a tensile load
applied at tip of the blade, for airfoil No.
1, is shown in Eig. T.
The holographic interference patterns were ob-.
served from five different directions through
eaeh hologram; in particular, observation
directions 7, 2, 4, 6, and 8, see Fig. 6,
were used to obtain necessary parameters to
solve Eg. 11.
Partial displacements from each of the holo-
grams were added up algebraically and the fi-
nal tensile test results for airfoil No. 1
are presented in Figs 8 and 9, where the co-
ordinates of the airfoil were nondimensiona-
lized with respect to the cord at the corre-
sponding grid level. Figure 8 gives the re-
sults at a grid level 26 (see Fig. 3) whereas
Fig. 9 shows deflections at level 11. The ex-
perimental results presented in these figures
show that for a blade in tension, maximum dis-
placements occured at the leading edge. More
specifically, for a tensile load of 2,061 lbs
applied at tip of the blade, the components
of the displacement vector at level 26 were:
d, = -79.52 um, d, = 160.56 yum, and d, s
204.51 um, while those at level 11 were: d, =
-25.28 um, d, = 104.00 ym, and d, = 120.23 um.
For this reason, the deflections presented in
Figs 8 and 9 were magnified sixty (60) times
in order to amplify the differences between
the initial and final positions of the airfoil.
Furthermore, the experimental results presented
in Fig. 9 are compared with the theoretical
results obtained from finite element analysis
of the airfoil. As is clearly seen from this
figure, the agreement between the experiments
and theory is very good at the leading edge,