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214
SUA’ VE VÌA'G.
If we let sin a — s, and cos a = c, we have
L = sD + cL ± Vr - (.D■ + U) + (sD + cLf
(6)
H ere there are two values of l m which will satisfy the equa
tion, and so there are two solutions to the problem. If the
surveyor has no knowledge whatever of either the unknown
length or bearing, the problem is indeterminate. If he has
seen the tract he could usually tell which length or which
resulting bearing was the correct one, when the problem would
become determinate. When l m is found, substitute in one of
equations (5) and find 0 n . Pay careful attention to the signs
of the trigonometrical functions of all bearings. When the
two unknown courses are nearly at right angles with each
other the problem is impracticable.
Case III.— When two bearings are unknown.
Let /' and /" be the known lengths of the courses whose
bearings are unknown. Then the equations become
1' sin d m -f-1" sin 6 n
1' cos 6 m -|- l" cos 6 n
D-
L.
• • (7)
Whence
cos 0 n =
KL± D VL 2 - K 2 + D 2
D l + U
. (8)
Where
K =
- r -\-D' + r
21"
This case is also indeterminate unless one is able to tell
which of the two sets of bearings is the correct one.*
CASE IV.— When the lengths of two courses are unknown.
* And if the unknown sides are parallel, the problem is indeterminate.
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