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REPORT OF COMMISSION V GV—63
was that both Analyzers were taking records simultaneously. This is, of course,
not true, as in practice each Analyzer is being tracked independently and there
is no direct relation between the times of exposure. To overcome this requires
only a realization that, if it is possible to locate on the projected trajectory of
Analyzer B a point which would correspond to an image on the record of
Analyzer A, the problem returns to the one previously described. By examining
the sighting rays BR and AQ on the airplane image just to the right of P, it is
realized that together with the base line AB they form a plane, and, of course,
if the pictures were simultaneously recorded their rays must lie in such a plane.
PLANE OF SYMMETRY
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DISPLACEMENT O — PL cos O - xL cos Q SIN 90—
sin + ©
Fic. 8.
Now suppose the location of point R is not known but had to be found. If
mentally a line from point NN is drawn in the plane of symmetry and on the
base line through Q, and is projected on to the other projected trajectory ER,
it would intersect at R which is the position of the target on this trajectory at
the same instant as the record point Q was recorded.
In practice then, one would make such a determination and then obtain
KL by subtracting the vertical ordinates of these two points and compute O.
A second method uses two Analyzers set up on the same side of the flight
course along a base line A-B (See Figure 9). Here the aircraft is flying a climbing
curved course such as a missile might take on launching, OG and OF are the
projections on a vertical plane OCDE as recorded by Analyzers A and B which
are located on a base line parallel to plane OCDE and set R feet apart and M+L
feet from the base of the reference plane OE. It is again apparent that the two
operators will track individually and the missile images will not be recorded
simultaneously by both Analyzers. The condition necessary for two images to
be recorded simultaneously is that the image on the trajectory trace OF lies